log(2x^2+x)=1

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Solution for log(2x^2+x)=1 equation:


Simplifying
log(2x2 + x) = 1

Reorder the terms:
glo(x + 2x2) = 1
(x * glo + 2x2 * glo) = 1
(glox + 2glox2) = 1

Solving
glox + 2glox2 = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + glox + 2glox2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + glox + 2glox2 = 0

The solution to this equation could not be determined.

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